x-3=4(2x-5-x^2)

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Solution for x-3=4(2x-5-x^2) equation: 



x-3=4(2x-5-x^2)

We move all terms to the left:

x-3-(4(2x-5-x^2))=0



We calculate terms in parentheses: -(4(2x-5-x^2)), so:

4(2x-5-x^2)

We multiply parentheses

-4x^2+8x-20

Back to the equation:

-(-4x^2+8x-20)



We get rid of parentheses

4x^2-8x+x+20-3=0

We add all the numbers together, and all the variables

4x^2-7x+17=0

a = 4; b = -7; c = +17;
Δ = b2-4ac
Δ = -72-4·4·17
Δ = -223
Delta is less than zero, so there is no solution for the equation

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